2y^2+32y-384=0

Solution for 2y^2+32y-384=0 equation:

2y^2+32y-384=0

a = 2; b = 32; c = -384;
Δ = b2-4ac
Δ = 322-4·2·(-384)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-64}{2*2}=\frac{-96}{4}
=-24
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+64}{2*2}=\frac{32}{4}
=8
$